If a nurse administers clindamycin palmitate 225 mg, how many mL will be required if the concentration is 74 mg/5 mL?

To determine how many mL are needed to administer 225 mg of clindamycin palmitate when the concentration is 74 mg per 5 mL, we can set up a proportion based on the concentration.

First, we find out how many mg are present in each mL of the solution. Given the concentration of 74 mg in 5 mL, we can calculate the amount in 1 mL:

74 mg/5 mL = 14.8 mg/mL.

Next, to find out how many mL are needed for 225 mg, we can use the formula:

Volume (mL) = Dose (mg) / Concentration (mg/mL).

Substituting in the values we have:

Volume = 225 mg / 14.8 mg/mL ≈ 15.19 mL.

Since the question asks for the number of mL required, you would round this to the nearest whole number or contextually appropriate amount, leading us to select 15 mL as the correct answer.

This choice corresponds with the calculation based on the provided concentration, ensuring that the patient receives the correct dosage of the medication.